Laplace Transform. L{e^(2t) sin(t)}

Laplace Transform

L{e^2t sin(t)}

L{e^at f(t)} = F(s-a) where F(s) = L{f(t)}

L{sin(t)} = 1 s² + 1

Since a = 2, s → s - 2

L{e^2t sin(t)} = 1 (s-2)² + 1